7x^2-3x+8=4x-4

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Solution for 7x^2-3x+8=4x-4 equation: 



7x^2-3x+8=4x-4

We move all terms to the left:

7x^2-3x+8-(4x-4)=0

We get rid of parentheses

7x^2-3x-4x+4+8=0

We add all the numbers together, and all the variables

7x^2-7x+12=0

a = 7; b = -7; c = +12;
Δ = b2-4ac
Δ = -72-4·7·12
Δ = -287
Delta is less than zero, so there is no solution for the equation

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